building an array project - error message error C2660: 'FindAvg' : function does not take 1 parameters
Thu, 2012-03-22 21:47
This is the only error message I have left to fix. I've tried everything I can think of. Please help!
Here is where it points the error message too:
//find the average of numbers in array a
float Average;
FindAvg(a);
this is the related user defined function:
void FindAvg(int a[])
{
int Total = 0;
for (int i = 1; i < 10; ++i)
{
Total += a[i];
}
float Average = Total/10;
}
If more information is needed, please let me know.
Thanks, anyone who can help!
Fri, 2012-03-23 18:24
#2
Thanks! I will give this a try. Also, thanks for including "why" I need to write it that way. It's difficult to get help from my classmates! I think they want to keep all the information to themselves! Hahaha! Or I just need to reconsider my major, this is some very difficult stuff! :-)
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The required parameter for FindAvg is an array of intergers. You are passing a single float. The problem is that you are passing the wrong type of argument.
this should work
#include "stdio.h" ////// I wrote this in C, but this function will work in a C++ program too
float FindAvg(float a[], int size) /// you need to specify how many elements are in the array
/// I also would expect that you want to return the average so that's why I have it return a float
{
float Total = 0.0;
int i;
for (i = 0; i < size; i++) /// arrays start at 0 not 1 /// also use the postincrement operator "i++" instead
{
Total += a[i];
}
float Average = Total/size;
return Average;
}
int main()
{
float myNumbers[] = { 1.2, 2.3, 3.4 }; ////// you can change and/or add values
printf("%f\n",FindAvg(myNumbers, sizeof(myNumbers)/sizeof(float))) ;
return 0; // the sizeof operator tells how many bytes something takes up in memory
/// so if you take the total number of bytes in the elemetns take up and divide that number
/// by the size of each element, then you get the number of elements
}